Processing math: 100%
Formula 10.4.28
H
(
1
)
2
/
3
(
ζ
)
=
e
−
2
π
i
/
3
H
(
1
)
−
2
/
3
(
ζ
)
=
e
π
i
/
6
(
√
3
/
z
)
[
A
i
′
(
−
z
)
−
i
B
i
′
(
−
z
)
]
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