Formula 10.4.28

$$ \begin{split} H^{(1)}_{2/3} (\zeta) &= e ^{-2\pi \ i/3} H^{(1)}_{-2/3} (\zeta) \\ &= e^{\pi \ i/6} (\sqrt 3/z) \ [\mathrm{Ai'} \ (-z) -i \ \mathrm{Bi'}\ (-z)] \end{split} $$ Torna alla Home