Che bella formula: $$\mathrm{Bi}(ze^{\pm \pi i/3})\sim \sqrt{2/\pi} e^{\pm \pi i/6}z^{-\frac{1}{2}}\bigg[ \mathrm{sin}\Big( \xi+\frac{\pi}{4}\mp \frac{i}{2}\mathrm{ln}\, 2\Big) \sum_{0}^{\infty} (-1)^{k}c_{2k} \xi ^{-2k} -\mathrm{cos}\Big( \xi+\frac{\pi}{4} \mp \frac{i}{2}\mathrm{ln}\, 2\Big) \sum_{0}^{\infty}(-1)^{k}c_{2k+1} \xi ^{-2k-1}\bigg]\qquad (|\mathrm{arg}\,z|< \frac{2}{3} \pi)$$
Clicca qui per tornare alla pagina principale.